JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank Self Evaluation Test - Principle of Mathematical Induction

  • question_answer
    For a positive integer n, Let \[a(n)=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{({{2}^{n}})-1}.\] Then

    A) \[a(100)\le 100\]

    B) \[a(100)>100\]

    C) \[a(200)\le 100\]

    D) \[a(200)<100\]

    Correct Answer: A

    Solution :

    [a] It can be proved with the help of mathematical induction that \[\frac{n}{2}>a(n)\le n.\] \[\therefore \,\,\,\,\frac{200}{2}<a(200)\] \[\Rightarrow a(200)>100\] and \[a(100)\le 100.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner