A) \[h\cot \theta \]
B) \[h\cos \theta \sec \frac{\theta }{2}\]
C) \[h\cot \theta \sin \frac{\theta }{2}\]
D) \[h\cos \theta \cos ec\frac{\theta }{2}\]
Correct Answer: B
Solution :
[b] \[OA=OB=h\cot \theta \] Now, \[AB=2AN=2AO\sin \frac{\theta }{2}\] \[=2h\frac{\cos \theta }{\sin \theta },\sin \frac{\theta }{2}=h\cos \theta \sec \frac{\theta }{2}\]You need to login to perform this action.
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