A) \[0.8\,mA\]
B) \[0.6\,mA\]
C) \[0.4\,mA\]
D) \[1\,mA\]
Correct Answer: B
Solution :
[b] \[{{g}_{m}}=\frac{\Delta {{I}_{p}}}{\Delta {{V}_{g}}}\] or \[\Delta {{I}_{p}}={{g}_{m}}\times \Delta {{V}_{g}}=3\times {{10}^{-4}}\times [-3-(-1)]\] \[=-0.6\times {{10}^{-3}}A=\]shortage of \[0.6\times {{10}^{-3}}A\]You need to login to perform this action.
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