A) 6, 3
B) 9, 5
C) 12, 7
D) 3, 1
Correct Answer: A
Solution :
[a] Let two numbers be a and b. Given \[\frac{2ab}{a+b}=4\Rightarrow ab=2\left( a+b \right)\] \[2A+{{G}^{2}}=27\] \[\Rightarrow \,\,\,\,2\left( \frac{a+b}{2} \right)+ab=27\] \[\Rightarrow \,\,\,\,ab=18\] and \[a+b=9\Rightarrow ab=9\] On solving these we get \[a=3\] & \[b=6\] or \[a=6\] & \[b=3.\]You need to login to perform this action.
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