A) \[0.3375\]
B) \[3.375\]
C) \[1.68\]
D) \[0.025\]
Correct Answer: B
Solution :
[b] \[{{V}_{c}}=\frac{60}{0.80}=75c{{m}^{3}}mo{{l}^{-1}};\] \[b=\frac{{{V}_{c}}}{3}=25c{{m}^{3}}mo{{l}^{-1}};=0.25Lmo{{l}^{-1}}\] \[\therefore {{T}_{c}}=\frac{8a}{27Rb}\] \[\frac{4\times {{10}^{5}}}{821}=\frac{2.45}{0.425}=5.76\,g{{L}^{-1}}\] \[\Rightarrow a=3.375\]You need to login to perform this action.
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