A) 0
B) 1/2
C) 3/2
D) \[-3/2\]
Correct Answer: D
Solution :
[d] \[{{C}_{6}}{{H}_{6}}(l)+\frac{15}{2}{{O}_{2}}(g)\to 6C{{O}_{2}}(g)+3{{H}_{2}}O(l)\] \[\therefore \Delta n=6-15/2=-3/2\]You need to login to perform this action.
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