A) \[3.2\text{ }kcal\text{ }mo{{l}^{-1}}\]
B) \[2.0\text{ }kcal\text{ }mo{{l}^{-1}}\]
C) \[3.0\text{ }kcal\text{ }mo{{l}^{-1}}\]
D) \[4.0\text{ }kcal\text{ }mo{{l}^{-1}}\]
Correct Answer: B
Solution :
[b] \[{{\Delta }_{neu}}H\]for strong base and strong acid \[=-13.7\text{ }kcal\,e{{q}^{-1}}\] \[\Delta {{H}_{ion}}(C{{H}_{3}}COOH)\] \[=-12.5-\left( -13.7 \right)=1.2\text{ }kcalmo{{l}^{-1}}\] \[\Delta {{H}_{ion}}(N{{H}_{4}}OH)\] \[=-10.5-(-13.7)-\Delta {{H}_{ion}}(C{{H}_{3}}COOH)\] \[=13.7-10.5-1.2\] \[=2\text{ }kcal\,mo{{l}^{-1}}\]You need to login to perform this action.
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