A) \[\approx 167\text{ }cal\]
B) \[\approx 500\text{ }cal\]
C) 540 cal
D) 58 cal
Correct Answer: B
Solution :
[b] \[dW=P\Delta V=1.01\times {{10}^{5}}\left[ 1671-1 \right]\times 10-6\text{ }Joule\] \[=\frac{1.01\times 167}{4.2}cal.=40\text{cal}\text{. nearly}\] \[\Delta Q=mL=1\times 540.\] \[\Delta Q=\Delta W+\Delta U\] \[\text{or }\Delta U=540-40=500\text{ cal}\text{. }\]You need to login to perform this action.
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