A) \[(1,2,3)\]
B) \[(2,4,6)\]
C) \[\left( \frac{4}{3},\frac{8}{3},\frac{12}{3} \right)\]
D) None of these
Correct Answer: B
Solution :
[b] Let any point on the second line be \[(\lambda ,2\lambda ,3\lambda )\] \[\cos \theta =\frac{6}{\sqrt{42}},\sin \theta =\frac{\sqrt{6}}{\sqrt{42}}\] \[{{\Delta }_{OAB}}=\frac{1}{2}(OA)\,\,OB\,\,sin\theta \] \[=\frac{1}{2}\sqrt{3}\lambda \sqrt{14}\times \frac{\sqrt{6}}{\sqrt{42}}=\sqrt{6}or\lambda =2\] So, B is (2, 4, 6)You need to login to perform this action.
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