A) 41cm
B) 37cm
C) 31cm
D) 80cm
Correct Answer: A
Solution :
[a] For open pipe, \[n=\frac{v}{2\ell }\], where \[{{n}_{0}}\] is the fundamental frequency of open pipe. \[\therefore \,\,\,\ell =\frac{v}{2n}=\frac{330}{2\times 300}=\frac{11}{20}\] As freq. of 1 st overtone of open pipe = freq. of 1 st overtone of closed pipe \[\therefore \,\,2\frac{v}{2\ell }=3\frac{v}{4\ell '}\] \[\Rightarrow \ell '=\frac{3\ell }{4}=\frac{3}{4}\times \frac{11}{20}=41.25cm\]You need to login to perform this action.
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