A) 1/8
B) 4/9
C) 2/3
D) 8/9
Correct Answer: D
Solution :
[d] \[\frac{{{E}_{r}}}{{{E}_{i}}}={{\left( \frac{{{A}_{r}}}{{{A}_{i}}} \right)}^{2}}={{\left( \frac{{{V}_{2}}-{{V}_{1}}}{{{V}_{1}}+{{V}_{2}}} \right)}^{2}}=1/9\] Therefore, \[\frac{{{E}_{t}}}{{{E}_{i}}}=8/9\]You need to login to perform this action.
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