A) \[ct/\pi \]
B) \[ct/2\pi \]
C) \[\pi /2k\]
D) \[\pi /k\]
Correct Answer: D
Solution :
[d] \[y=A\sin (kx-kct)+A\sin (kx+kct)\] \[=2\,A\,\sin \] \[\left( \frac{kx-kct+kx+kct}{2} \right).\cos \left( \frac{kx-kct-kx-kct}{2} \right)\] \[=2\,A\,\sin (kct).cos\,kx.\] Thus\[\frac{2\pi }{\lambda }=k\], \[\therefore \lambda =\frac{2\pi }{k}\] The distance between adjacent nodes \[=\frac{\lambda }{2}=\frac{\pi }{k}\]You need to login to perform this action.
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