A) \[A\cap B=\varphi \]
B) \[A\cap B\ne \varphi \]
C) \[A\cup B={{R}^{2}}\]
D) None of these
Correct Answer: B
Solution :
\[\because y={{e}^{x}},\,\,y={{e}^{-x}}\]will meet, when \[{{e}^{x}}={{e}^{-x}}\] Þ \[{{e}^{2x}}=1,\,\,\therefore x=0,y=1\] \ A and B meet on (0, 1), \ \[A\cap B=\varphi \].
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