A) \[A-B=A\cup B\]
B) \[A-B=A\cap B\]
C) \[A-B={{A}^{c}}\cap B\]
D) \[A-B=A\cap {{B}^{c}}\]
Correct Answer: D
Solution :
\[A-B=\{x:x\in A\]and \[x\not{\in }B\}\] \[=\{x:x\in A\]and \[x\in {{B}^{c}}\}=A\cap {{B}^{c}}\].
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