A) \[{{2}^{99}}\]
B) \[{{99}^{2}}\]
C) 100
D) 18
E) 9
Correct Answer: B
Solution :
\[n((A\times B)\cap (B\times A))\] \[=n((A\cap B)\times (B\cap A))=n(A\cap B).n(B\cap A)\] \[=n(A\cap B).n(A\cap B)=(99)(99)={{99}^{2}}\].
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