A) \[\frac{3}{7}\]
B) \[\frac{4}{7}\]
C) \[\frac{2}{3}\]
D) \[\frac{3}{5}\]
Correct Answer: B
Solution :
Let the numerator of the original fraction be x. Then its denominator is \[x+3\]. \[\Rightarrow \] Original fraction \[=\frac{x}{x+3}\] \[\Rightarrow \] \[\frac{x+2}{x+5}=\frac{2}{3}\](Given) \[\Rightarrow x=4\] \[\therefore \] Original fraction \[=\frac{4}{7}\]You need to login to perform this action.
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