A) \[\sqrt{T}\]
B) T
C) \[{{T}^{1/3}}\]
D) \[\sqrt{2}\]T
Correct Answer: D
Solution :
\[T=2\pi \sqrt{\frac{l}{g}}\Rightarrow T\propto \frac{1}{\sqrt{g}}\]\[\Rightarrow \frac{{{T}_{P}}}{{{T}_{e}}}=\sqrt{\frac{{{g}_{e}}}{{{g}_{P}}}}=\sqrt{\frac{2}{1}}\Rightarrow T'=\sqrt{2}T\]
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