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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Simple Pendulum

  • question_answer
    The acceleration due to gravity at a place is\[{{\pi }^{2}}\,m/se{{c}^{2}}\]. Then the time period of a simple pendulum of length one metre is                                               [JIPMER 2002]

    A)            \[\frac{2}{\pi }sec\]           

    B)            \[2\pi \,sec\]

    C)            \[2\,sec\]                              

    D)            \[\pi \,sec\]

    Correct Answer: C

    Solution :

               \[T=2\pi \sqrt{l/g}=2\pi \sqrt{\frac{1}{{{\pi }^{2}}}}\]= 2 sec


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