A) \[\sqrt{2/3}\]
B) \[\sqrt{3/2}\]
C) \[4/9\]
D) \[9/4\]
Correct Answer: D
Solution :
Frequency \[n\propto \frac{1}{\sqrt{\text{l}}}\]Þ \[\frac{{{n}_{1}}}{{{n}_{2}}}=\sqrt{\frac{{{l}_{2}}}{{{l}_{1}}}}\]Þ\[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{n_{2}^{2}}{n_{1}^{2}}=\frac{{{3}^{2}}}{{{2}^{2}}}=\frac{9}{4}\]
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