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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Simple Pendulum

  • question_answer
    A pendulum of length 2m lift at P. When it reaches Q, it losses 10% of its total energy due to air resistance. The velocity at Q is                                                          [DCE 1998]

    A)            6 m/sec

    B)            1 m/sec

    C)            2 m/sec

    D)            8 m/sec

    Correct Answer: A

    Solution :

                       If v is velocity of pendulum at Q                    and 10% energy is lost while moving from P to Q Hence, by applying conservation of between P and Q            \[\frac{1}{2}m{{v}^{2}}=0.9\,(mgh)\]Þ\[{{v}^{2}}=2\times 0.9\times 10\times 2\]Þ \[v=6\,m/sec\]


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