A) \[a,\frac{1}{a}\]
B) a, 2a
C) \[a,\frac{1}{2a}\]
D) None of these
Correct Answer: A
Solution :
Equation \[a({{x}^{2}}+1)-({{a}^{2}}+1)x=0\] Þ\[a{{x}^{2}}-({{a}^{2}}+1)x+a=0\] Þ \[(ax-1)(x-a)=0\]Þ \[x=a,\frac{1}{a}\].You need to login to perform this action.
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