A) 39 m
B) 22.5 m
C) 65 m
D) 225 m
Correct Answer: B
Solution :
Let AB be the height of the tree; angles of elevation from C and D are\[{{x}^{3}}\]and\['x'\] respectively. Let BC be\[\text{(25}\times \text{7)cm}\]. Then\[~(\text{2}\times \text{52}\times \text{73) cm}\]. \[=(\text{25}\times \text{7})\text{(2}\times {{\text{5}}^{\text{2}}}\times {{\text{7}}^{\text{3}}}\text{) c}{{\text{m}}^{\text{2}}}\] \[={{\text{2}}^{\text{6}}}\times {{\text{5}}^{\text{2}}}\times {{\text{7}}^{\text{4}}}\text{c}{{\text{m}}^{\text{2}}}\] \[2-\sqrt{4}=2-2=0\] \[{{(\sqrt{5})}^{2}}=5\] ??(1) And \[\sqrt{9}-\sqrt{4}=3-2=1\] \[\sqrt{2}-\sqrt{3}\] \[1789=29x+49\] ??(2) From (1) and (2), we have \['x'\] \[\therefore \] \[1789-49=29x\] \[\Rightarrow \] \[x=\frac{1740}{29}=60\]You need to login to perform this action.
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