10th Class Science Sources of Energy Question Bank Sources of Energy

  • question_answer
     An electric field of intensity \[6\times 104volts/m\] is applied perpendicular to the direction of motion of the electron. A magnetic field of intensity \[\text{8 }\times \text{ 1}{{0}^{-\text{2}}}\text{ wb}/{{\text{m}}^{\text{2}}}\]is applied perpendicular to both the electric field and direction of motion of the electron. What is the velocity of the electron if it passes un deflected?

    A)  \[\text{7}.\text{5 }\times \text{ 1}{{0}^{\text{5}}}\text{ m}/\text{s}\]  

    B)  \[\text{7}.\text{5 }\times \text{ 1}{{0}^{-\text{5}}}\text{ m}/\text{s}\]

    C)  \[\text{6}\times \text{ 1}{{0}^{\text{4}}}\times \text{8 }\times \text{ l}{{\text{0}}^{-\text{2}}}\text{ m}/\text{s}\]

    D)  It is never possible

    Correct Answer: A

    Solution :

     In case of no deviation,\[eE=evB\] \[\therefore \]  \[v=\frac{E}{B}=\frac{6\times {{10}^{4}}}{8\times {{10}^{-2}}}\]                   \[\mathbf{=7}\mathbf{.5\times 1}{{\mathbf{0}}^{\mathbf{5}}}\mathbf{m/sec}\].


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