10th Class Science Sources of Energy Question Bank Sources of Energy

  • question_answer
    An electron is moving with velocity 107 m/s on a circular path of radius 0.57 cm in a magnetic field of\[\text{1}{{0}^{-\text{2}}}\text{ wb}/{{\text{m}}^{\text{2}}}\]. The value of elm for electron will  be

    A) \[\text{1}\text{.76 }\times \text{ 1}{{0}^{\text{9}}}\text{ C}/\text{kg}\]               

    B)  \[\text{1}\text{.76 }\times \text{ 1}{{0}^{\text{1}0}}\text{ C}/\text{kg}\]

    C) \[\text{1}\text{.76 }\times \text{ 1}{{0}^{\text{11}}}\text{ C}/\text{kg}\]               

    D)  \[\text{1}\text{.76 }\times \text{ 1}{{0}^{\text{12}}}\text{ C}/\text{kg}\]

    Correct Answer: C

    Solution :

     We know,          \[evB=\frac{m{{v}^{2}}}{r}\] \[\Rightarrow \]               \[\frac{e}{m}=\frac{v}{Br}=\frac{{{10}^{7}}}{{{10}^{-2}}\times 0\cdot 0057}\]                     \[\mathbf{=1}\mathbf{.76\times 1}{{\mathbf{0}}^{\mathbf{11}}}\mathbf{C/kg}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner