JEE Main & Advanced Physics Ray Optics Question Bank Spherical Mirror

  • question_answer
    In a concave mirror experiment, an object is placed at a distance \[{{x}_{1}}\] from the focus and the image is formed at a distance \[{{x}_{2}}\] from the focus. The focal length of the mirror would be                                     [MP PET 1997]

    A)            \[{{x}_{1}}{{x}_{2}}\]        

    B)            \[\sqrt{{{x}_{1}}{{x}_{2}}}\]

    C)            \[\frac{{{x}_{1}}+{{x}_{2}}}{2}\]                                      

    D)            \[\sqrt{\frac{{{x}_{1}}}{{{x}_{2}}}}\]

    Correct Answer: B

    Solution :

                       Given \[u=(f+{{x}_{1}})\] and \[v=(f+{{x}_{2}})\]                    The focal length \[f=\frac{uv}{u+v}=\frac{(f+{{x}_{1}})(f+{{x}_{2}})}{(f+{{x}_{1}})+(f+{{x}_{2}})}\]            On solving, we get \[{{f}^{2}}={{x}_{1}}{{x}_{2}}\] or \[f=\sqrt{{{x}_{1}}{{x}_{2}}}\]


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