A) Real and at \[20\,cm\] from the mirror
B) Virtual and at \[20\,cm\] from the mirror
C) Virtual and at \[20/3\,cm\] from the mirror
D) Real and at \[20/3\,cm\] from the mirror
Correct Answer: C
Solution :
\[u=-20\,cm,\] \[f=+10\,cm\] also \[\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\] \[\Rightarrow \frac{1}{+10}=\frac{1}{v}+\frac{1}{(-20)}\Rightarrow v=\frac{20}{3}\,\,cm;\]virtual image.You need to login to perform this action.
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