A) \[0.4cm\] away from the mirror
B) \[0.4cm\]towards the mirror
C) \[0.8cm\] away from the mirror
D) \[0.8cm\] towards the mirror
Correct Answer: A
Solution :
Mirror formula \[\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\Rightarrow \frac{1}{f}=\frac{1}{-20}+\frac{1}{(-10)}\Rightarrow f=\frac{20}{3}\,\,cm.\] If object moves towards the mirror by \[0.1\,cm\] then. \[u=(10-0.1)=9.9\,cm.\] Hence again from mirror formula \[\frac{1}{-20/3}=\frac{1}{{{v}'}}+\frac{1}{-9.9}\Rightarrow {v}'=20.4\,cm\] i.e. image shifts away from the mirror by \[0.4\,cm.\]
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