A) 2T
B) T
C) \[\frac{T}{\sqrt{2}}\]
D) \[\frac{T}{2}\]
Correct Answer: D
Solution :
\[T\propto \frac{1}{\sqrt{k}}\] Þ \[\frac{{{T}_{2}}}{{{T}_{1}}}=\sqrt{\frac{{{K}_{1}}}{{{K}_{2}}}}\]\[=\sqrt{\frac{k}{4k}}=\frac{1}{2}\]Þ \[{{T}_{2}}=\frac{{{T}_{1}}}{2}\]
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