JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Spring Pendulum

  • question_answer
    A weightless spring of length 60 cm and force constant 200 N/m is kept straight and unstretched on a smooth horizontal table and its ends are rigidly fixed. A mass of 0.25 kg is attached at the middle of the spring and is slightly displaced along the length. The time period of the oscillation of the mass is                                             [MP PET 2003]

    A)            \[\frac{\pi }{20}s\]             

    B)            \[\frac{\pi }{10}s\]

    C)            \[\frac{\pi }{5}s\]               

    D)            \[\frac{\pi }{\sqrt{200}}s\]

    Correct Answer: A

    Solution :

                       System is equivalent to parallel combination of springs    \\[{{K}_{eq}}={{K}_{1}}+{{K}_{2}}=400\] and            \[T=2\pi \sqrt{\frac{m}{{{K}_{eq}}}}=2\pi \sqrt{\frac{0.25}{400}}=\frac{\pi }{20}\]


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