JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Spring Pendulum

  • question_answer
    If a body of mass 0.98 kg is made to oscillate on a spring of force constant 4.84 N/m, the angular frequency of the body is                                                                                   [CBSE PMT 2001]

    A)            1.22 rad/s                              

    B)            2.22 rad/s                              

    C)            3.22 rad/s                              

    D)            4.22 rad/s

    Correct Answer: B

    Solution :

               \[\omega =\sqrt{k/m}=\sqrt{\frac{4.84}{0.98}}=2.22\ rad/\sec \]


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