A) 2 : 1
B) 1 : 1
C) 1 : 2
D) 4 : 1
Correct Answer: C
Solution :
\[n=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] Þ \[\frac{{{n}_{S}}}{{{n}_{P}}}=\sqrt{\frac{{{k}_{S}}}{{{k}_{P}}}}\]\[\Rightarrow \] \[\frac{{{n}_{s}}}{{{n}_{p}}}=\sqrt{\frac{\left( \frac{k}{2} \right)}{2k}}=\frac{1}{2}\]
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