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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Static and Limiting Friction

  • question_answer
    A 20 kg block is initially at rest on a rough horizontal surface.  A horizontal force of 75 N is required to set the block in motion.  After it is in motion, a horizontal force of 60 N is required to keep the block moving with constant speed.  The coefficient of static friction is        [AMU 1999]

    A)             0.38

    B)             0.44

    C)             0.52    

    D)             0.60

    Correct Answer: A

    Solution :

                    Coefficient of friction \[{{\mu }_{s}}=\frac{{{F}_{l}}}{R}=\frac{75}{mg}=\frac{75}{20\times 9.8}\]\[=0.38\]           


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