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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Static and Limiting Friction

  • question_answer
    A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N.  The coefficient of friction between wall and body is 0.3. Then the frictional force is equal to                                                 [Orissa JEE 2003]

    A)             6 N     

    B)             20 N

    C)               600 N 

    D)             700 N

    Correct Answer: B

    Solution :

                    For the given condition, Static friction   = Applied force = Weight of body \[=2\times 10=20\ N\]


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