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JEE Main & Advanced Physics Wave Mechanics Question Bank Stationary Waves

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    The stationary wave produced on a string is represented by the equation\[y=5\cos (\pi x/3)\sin 40\pi t\]. Where x and y are in cm and \[t\] is in seconds. The distance between consecutive nodes is                                   [MP PMT 2000]

    A)            5 cm                                         

    B)            \[\pi \] cm

    C)            3 cm                                         

    D)            40 cm

    Correct Answer: C

    Solution :

                 On comparing the given equation with standard equation \[\Rightarrow \frac{2\pi }{\lambda }=\frac{\pi }{3}\Rightarrow \lambda =6\,cm\]. Hence, distance between two consecutive nodes Þ l = 3 cm


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