question_answer

The phase difference between the two particles situated on both the sides of a node is                [MP PET 2002]

A)            0°   

B)            90°

C)            180°                                         

D)            360°

Correct Answer: C

Solution :

                     Both the sides of a node, two antinodes are present with separation \[\frac{\lambda }{2}\] So phase difference between then \[\varphi =\frac{2\pi }{\lambda }\times \frac{\lambda }{2}=\pi \]