A) \[{{z}_{1}}+{{z}_{2}}\]
B) \[{{z}_{2}}+{{z}_{3}}\]
C) \[{{z}_{3}}+{{z}_{1}}\]
D) \[{{z}_{1}}+{{z}_{2}}+{{z}_{3}}\]
Correct Answer: A
Solution :
Waves \[{{Z}_{1}}=A\sin (kx-\omega t)\] is travelling towards positive x-direction. Wave \[{{Z}_{2}}=A\sin (kx+\omega t)\], is travelling towards negative x-direction. Wave \[{{Z}_{3}}=A\sin (ky-\omega t)\] is travelling towards positive y direction. Since waves Z1 and Z2 are travelling along the same line so they will produce stationary wave.
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