JEE Main & Advanced Physics Wave Mechanics Question Bank Stationary Waves

  • question_answer
    The equation of a stationary wave is \[y=0.8\cos \,\left( \frac{\pi x}{20} \right)\sin 200\,\pi t\], where x is in cm and t is in sec. The separation between consecutive nodes will be [MP PET 1994]

    A)            20 cm                                      

    B)            10 cm

    C)            40 cm                                      

    D)            30 cm

    Correct Answer: A

    Solution :

                         On comparing the given equation with standard equation \[y=2a\sin \frac{2\pi x}{\lambda }\cos \,\frac{2\pi vt}{\lambda }\]] We get \[\frac{2\pi }{\lambda }=\frac{\pi }{20}\Rightarrow \lambda =40\] Separation between two consecutive nodes = \[\frac{\lambda }{2}=\frac{40}{2}=20\,\,cm\]


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