10th Class Mathematics Statistics Question Bank Statistics and Probability

  • question_answer
    A student obtained the following marks percentage in an examination : English - 50, Accounts - 75, Economics - 60, B. Std. - 80, Hindi - 55. If weights are 2, 3, 3, 2, 1 respectively allotted to the subjects, his weighted mean is

    A)  \[\frac{\text{5}0+\text{75}+\text{6}0+\text{8}0+\text{55}}{\text{2}+\text{3}+\text{3}+\text{2}+\text{1}}\]

    B) \[\frac{~\left( \text{5}0\times \text{2} \right)+\left( \text{75}\times \text{3} \right)+\left( \text{6}0\times \text{3} \right)+\left( \text{8}0\times \text{2} \right)+\left( \text{55}\times \text{1} \right)}{5}\]

    C)  \[\frac{\text{5}0\times \text{2}+\text{75}\times \text{3}+\text{6}0\times \text{3}+\text{8}0\times \text{2}+\text{55}\times \text{1}}{\text{2}+\text{3}+\text{3}+\text{2}+\text{1}}\]  

    D)  none

    Correct Answer: C

    Solution :

     \[\therefore \] Geometric Mean \[={{(2\times 6\times 824)}^{\frac{1}{4}}}\] \[={{({{2}^{8}}\times {{3}^{2}})}^{\frac{1}{4}}}={{2}^{2}}\times {{3}^{\frac{1}{2}}}\] \[=4\sqrt{3}=\sqrt{48}\]


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