A) \[\frac{(n-1)(2n+1)}{6}\]
B) \[\frac{n+1}{6}\]
C) \[\frac{{{n}^{2}}-1}{6}\]
D) None of these
Correct Answer: A
Solution :
(a): Standard formula tor Sum\[=\frac{n(n+1)(2n+1)}{6}\] \[\therefore \] Mean \[=\frac{(n+1)(2n+1)}{6}\]
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