A) \[nM+a\]
B) \[\frac{nM-a}{2}\]
C) \[\frac{nM+a}{2}\]
D) \[\frac{nM-a}{4}\]
Correct Answer: D
Solution :
(d): Sum = nM Sum of (n ? 4) observations = a \[\therefore \] Sum of 4 observations \[=(nM-a)\] \[\therefore \] Mean of 4 observations \[=\frac{nM-a}{4}\]
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