A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
\[{{\sigma }_{1}}=3\sigma ,\] \[{{\sigma }_{2}}=0\] \[{{\tau }_{\max }}=\frac{{{\sigma }_{1}}-{{\sigma }_{2}}}{2}=\frac{3\sigma -\sigma }{2}=\sigma \] \[\frac{{{\sigma }_{1}}}{{{\tau }_{\max }}}=\frac{3\sigma }{\sigma }=3\]You need to login to perform this action.
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