A) \[{{\varepsilon }_{1}}+2{{\varepsilon }_{2}}\]
B) \[{{\varepsilon }_{1}}+{{\varepsilon }_{2}}^{2}\]
C) \[2{{\varepsilon }_{1}}+{{\varepsilon }_{2}}\]
D) \[{{\varepsilon }_{1}}^{2}+{{\varepsilon }_{2}}\]
Correct Answer: C
Solution :
\[{{\varepsilon }_{\theta }}=\frac{1}{E}({{\varepsilon }_{\theta }}-v{{\sigma }_{1}})={{\varepsilon }_{1}}\] \[{{\varepsilon }_{2}}=\frac{1}{E}({{\sigma }_{1}}-v{{\sigma }_{\theta }})={{\varepsilon }_{2}}\] \[V=\pi dl\] \[InV=In\,\pi +2\,In\,d+In\,l\] \[\frac{\delta \,V}{V}=2\frac{\delta d}{d}+\frac{\delta l}{l}\] \[{{\varepsilon }_{0}}=2{{\varepsilon }_{1}}+{{\varepsilon }_{2}}\]
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