Railways Technical Ability Engineering Mechanics and Strength of Materials Question Bank Strength of Materials

  • question_answer Bending moment M and torque T is applied on a solid circular shaft. If the maximum bending stress equals to maximum shear stress developed, then M is equal to:

    A) \[\frac{T}{2}\]                          

    B) T

    C) 2T                               

    D) 4T

    Correct Answer: A

    Solution :

    Maximum bending stress, \[{{\sigma }_{\max }}=\frac{32M}{\pi {{d}^{2}}}\] Maximum shear stress \[{{\tau }_{\max }}=\frac{16T}{\pi {{d}^{3}}}\] For \[{{\sigma }_{\max }}={{\tau }_{\max }}\] \[M=\frac{T}{2}\]

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