• # question_answer Bending moment M and torque T is applied on a solid circular shaft. If the maximum bending stress equals to maximum shear stress developed, then M is equal to: A) $\frac{T}{2}$                          B) TC) 2T                               D) 4T

Maximum bending stress, ${{\sigma }_{\max }}=\frac{32M}{\pi {{d}^{2}}}$ Maximum shear stress ${{\tau }_{\max }}=\frac{16T}{\pi {{d}^{3}}}$ For ${{\sigma }_{\max }}={{\tau }_{\max }}$ $M=\frac{T}{2}$