A) \[\frac{T}{2}\]
B) T
C) 2T
D) 4T
Correct Answer: A
Solution :
Maximum bending stress, \[{{\sigma }_{\max }}=\frac{32M}{\pi {{d}^{2}}}\] Maximum shear stress \[{{\tau }_{\max }}=\frac{16T}{\pi {{d}^{3}}}\] For \[{{\sigma }_{\max }}={{\tau }_{\max }}\] \[M=\frac{T}{2}\]
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