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Railways NTPC (Technical Ability) Engineering Mechanics and Strength of Materials Question Bank Strength of Materials

  • question_answer
          A closely-coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is t. Half of the length of spring is cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in the new condition will be:             

    A) \[\text{1/2}\,\tau \]                    

    B) \[\tau \]

    C) \[\text{2}\,\tau \]                                   

    D) \[\text{4}\,\tau \]

    Correct Answer: B

    Solution :

    Shear stress in helical spring, \[\tau =\frac{8W{{D}_{m}}}{\pi {{d}^{3}}}\]             Shear stress does not depend on length of the spring                         \[{{\tau }_{2}}={{\tau }_{1}}=\tau \]


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