A) Hexane
B) Methane
C) n-butane
D) 2,3,4-trimethyl hexane
Correct Answer: D
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,H-}}\,\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,H-}}\,\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,H-}}\,C{{H}_{3}}\], it is a chiral compound.
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