A) 2, 3-Dichloropentane
B) 2, 3-Dichlorobutane
C) 2-Chlorobutane
D) 2-Hydroxypropanoic acid
Correct Answer: B
Solution :
\[\underset{\text{2 chlorobutane}}{\mathop{\underset{\ \ \ C{{H}_{3}}}{\mathop{\underset{H\ -\,\underset{|}{\mathop{C}}\,\,-\,H}{\overset{\ \ \ C{{H}_{3}}}{\mathop{H-\underset{|}{\overset{|}{\mathop{C}}}\,-Cl}}}\,}}\,}}\,\] \[\underset{\text{2, 3 dichlorobutane}}{\mathop{\underset{\ \ \ C{{H}_{3}}}{\mathop{\underset{H\ -\,\underset{|}{\mathop{C}}\,\,-\,Cl}{\overset{\ \ \ C{{H}_{3}}}{\mathop{H-\underset{|}{\overset{|}{\mathop{C}}}\,-Cl}}}\,}}\,}}\,\] \[\underset{\text{2, 3 dichloropentane}}{\mathop{\underset{\ \ \,C{{H}_{3}}}{\overset{\ \ \ C{{H}_{3}}}{\mathop{\underset{H\,-\,\underset{|}{\mathop{C}}\,\,-\,H}{\overset{H\,-\,\overset{|}{\mathop{C}}\,\,-\,Cl}{\mathop{H-\underset{|}{\overset{|}{\mathop{C}}}\,-Cl}}}\,}}}\,}}\,\] \[\underset{\text{2 hydroxy propanoic acid}}{\mathop{{{H}_{3}}C-\overset{OH\ \ \ \ \ \ \ }{\mathop{\underset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}\,-COOH}}\,}}\,\]
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