A) \[C{{H}_{3}}C{{H}_{2}}\underset{Cl\ }{\mathop{\underset{|}{\mathop{C}}\,H}}\,-C{{H}_{3}}\]
B) \[C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl\]
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHC{{l}_{2}}\]
D) None
Correct Answer: A
Solution :
2-chloro butane has a chiral carbon atom, hence only it will show optical activity and will possess two enantiomers (one chiral carbon atom). \[C{{H}_{3}}C{{H}_{2}}-\underset{Cl\ }{\mathop{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{{{C}^{\bullet }}}}}\,}}\,-}}\,C{{H}_{3}}\]
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