• # question_answer The number of possible isomers of butene are [Kerala (Engg.) 2002] A) 3 B) 2 C) 4 D) 5 E) 6

Solution :

$C{{H}_{3}}=CH-C{{H}_{2}}-C{{H}_{3}}$; $C{{H}_{3}}-CH=CH-C{{H}_{3}}$; $C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,=\,}}\,C{{H}_{2}}$

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