A) Chain isomers
B) Geometrical isomers
C) Position isomers
D) Tautomers
Correct Answer: A
Solution :
\[\underset{n-\text{butane}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}}}\,\] and \[\underset{\text{Iso}-\text{butane}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{3}}}}\,\]
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